Find the work done in moving a particle from the origin to x=4?

The force on a particle is described by 4x^3 + 2 at a point x along the x-axis. Find the work done in moving a particle from the origin to x=4.

Find the work done in moving a particle from the origin to x=4?
im going to explain this using calculus because it is easiest, if you dont know calculus then you can do this on your calculator by finding the area under the curve from 0 to 4





work is the area under the curve describing the force on a particle from the origin to 4, in this case





the integral of 4x^3+2 = x^4 + 2x


(4^4+2*4)-0 = 264


so the answer is 264 (joules if your using SI)