A horizontal trough with semicircular cross sections 5 feet in diameter contains oil with a weight density of 80 lb/ft^3. If the trough is 25 feet long and filled with oil to a depth of 3 feet, find the work required to pump all of the oil to the top of the tank?
Find the work required to pump all of the oil to the top of the tank?
∫(80)(1/2)pi(5/2)^2(25-y)dy, y from 0 t0 3
= 55,370.57 lb*ft
Reply:The top of which tank? You've described a trough. What does the tank have to do with it?
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